A simple pendulum is 7.00 m long. What is the period of simple harmonic motion f

Question

A simple pendulum is 7.00 m long. What is the period of simple harmonic motion for this pendulum if it is located in an elevator accelerating upward at 5.00 m/s2? Your response differs from the correct answer by more than 10%. Double check your calculations. s What is its period if the elevator is accelerating downward at 5.00 m/s2? Your response differs from the correct answer by more than 100%. s. What is the period of simple harmonic motion for the pendulum if it is placed in a truck that is accelerating horizontally at 5.00 m/s2? Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry

Explanation / Answer

a) T =2*pi*sqrt(L/g+a) = 4.32 s b) T = 7.59 s c) T = 5.31 s

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