The problem is, no scale is perfect. Let\'s assume for the time being that the a
ID: 2161886 • Letter: T
Question
The problem is, no scale is perfect. Let's assume for the time being that the angles are quite accurate, but you know based on your past experience that these scales can be off by as much as 3 N. This uncertainty propagates through any calculation that involves the measured quantities.By how much (in N) could your estimation of the weight of the box be off?
Hint: The easiest way to do this is by finding the highest and smallest possible values of the weight that can result from the range of values of the measured forces.
Weight of the box is 821 N (601 sin (60) + 425 sin (45)) - I just cannot wrap my head around this for some reason
Explanation / Answer
it will deviate 3 N from the actual value as per the question . therefore the weight of the box will be 821 N (601 sin (60) + 425 sin (45) +or - 3
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