A 9.40 10-3 kg bullet is fired horizontally into a 2.64-kg wooden block attached

Question

A 9.40 10-3 kg bullet is fired horizontally into a 2.64-kg wooden block attached to one end of a massless, horizontal spring (k = 853 N/m). The other end of the spring is fixed in place, and the spring is unstrained initially. The block rests on a horizontal, frictionless surface. The bullet strikes the block perpendicularly and quickly comes to a halt within it. As a result of this completely inelastic collision, the spring is compressed along its axis and causes the block/bullet to oscillate with an amplitude of 0.200 m. What is the speed of the bullet?

Explanation / Answer

V=(.200/9.40e-3)sqrt((9.40e-3 + 2.64)853) = 1011.46

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