An object is launched vertically from near the surface of the Earth at at veloci
ID: 2163653 • Letter: A
Question
An object is launched vertically from near the surface of the Earth at at velocity of 100.0 m/sa. How high does it go?
b. How long does it take to reach its maximum height?
c. What is its velocity at its maximum height?
d. What is its acceleration at its maximum height?
e. At what time(s) is its height 100.0 m?
f. What is the objects speed at 100.0 m?
g. What is the objects impact velocity (magnitude and direction)?
This question is meant for understanding what to do if asked these questions based on knowledge already known like gravity. I answered some but i want to compare to see if anyone else get the same answers.
Explanation / Answer
The value of g(accl. due to gravity) decreases with increase in height. If the body is placed at a height 'h' from the surface of the earth, then the new value of g, say gn is given by gn = g[1-(2h)/R] , where R is the radius of the earth. Assuming the value of R as approximately 6.4 x 10^6 m, we get gn = 9.8 [ 1- (2*2370*1000)/6.4*10^6 ] =7.258 m/s^2 (approx)
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