Based off of image E. m=12kg friction=.3 L=4.5m and angle= 25 degrees. What woul

Question

Based off of image E. m=12kg friction=.3 L=4.5m and angle= 25 degrees. What would a force diagram look like? what is the magnitude and direction of the normal force? what is the magnitude and direction of the friction force? what is the magnitude and riction of the acceleration of the object? if the mass is initally at the orgin on the slope and the velocity of 3m/s what is the coordinate of the mass at the time showiwn in the picture? if it goes all the way down the hill, at what time does it reach the bottom ofthe hill? if it does come to a stop before that time, when and where does it come to a stop? show all work if possible.

Explanation / Answer

normal force is perpendicular to the surface of length 4.5m and frictional force and acceleration will be along the surface of length 4.5m mgsin25-mgcos25 *0.3 =ma hence a =1.47 m/s^2 us v=u +at and s=ut+1/2 at^2 to find all answer wher a=1.47 and s=4.5 m

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