As you look out of your dorm window, a flower pot suddenly falls past. The pot i

Question

As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time (t) , and the vertical length of your window(Lw)is . Take down to be the positive direction, so that downward velocities are positive and the acceleration due to gravity is the positive quantity(g) .

Assume that the flower pot was dropped by someone on the floor above you (rather than thrown downward).

From what height h above the bottom of your window was the flower pot dropped?

Express your anwer in Lw, t, and g
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Explanation / Answer

let u be the velocity when the pot reaches the top of the window therefre Lw= ut + 0.5g(t^2) and let h1 be the initial height from the top of the window => h1 = 0.5g(t1^2) and u= g(t1) => h1 = u^2/2g and u = Lw- 0.5g(t^2)/(t) and therefore height from the bottom of the window = h1 + Lw = (Lw- 0.5g(t^2)/(t))^2/(2g) + Lw

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