A cameraman on a pickup truck is traveling westward at 21 km/h while he videotap

Question

A cameraman on a pickup truck is traveling westward at 21 km/h while he videotapes a cheetah that is moving westward 30 km/h faster than the truck. Suddenly, the cheetah stops, turns, and then run at 47 km/h eastward, as measured by a suddenly nervous crew member who stands alongside the cheetah's path. The change in the animal's velocity takes 2.2 s. What are the (a) magnitude of the cheetah's acceleration according to the cameraman and the (b) magnitude of the cheetah's acceleration according to the nervous crew member?

Please explain your answer

Explanation / Answer

(a)

acceleration = v/t

Cameramen sees:

an initail velocity of 37 km/h=10.28 m/s
a final velocity of -(47+23)*1000/3600 = -19.44 m/s

For the cameraman acceleration :

a = (-19.44-10.28)/1.6 = -18.58 m/s^2

Magnitude = 18.58 m/s^2 OR 66.88 km/h.s OR 240750 KM/h^2

(b)

For the stationary crew member

vi = 37+23 = 60 km/h
vf = 47 km/h

a = (47+60)/1.6 = 66.875 km/h.s OR 240750 KM/h^2

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