A particle undergoes three displacements. The first has a magnitude of 15 m and

Question

A particle undergoes three displacements. The first has a magnitude of 15 m and makes an angle of 27 degrees with the positive x axis. The second has a magnitude of 8.8 m and makes an angle of 131 degrees with the positive x axis. After the third displacement, the particle returns to its initial position. The magnitude of the third displacement is 15.45m. Find the angle of the third displacement (measured from the positive x axis, with counterclockwise positive within the limits of -180 degrees to +180 degrees). -answer in units of degrees

Explanation / Answer

To add or subtract vectors you add or subtract their components. Vector components are: x = r * cos(th) y = r * sin(th) In your problem: v1 = v3 = v1 + v2 = find v2 = = v3 - v1

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