In the figure here, a red car and a green car move toward each other in adjacent

Question

In the figure here, a red car and a green car move toward each other in adjacent lanes and parallel to an x axis. At time t = 0, the red car is at xr = 0 and the green car is at xg = 213 m. If the red car has a constant velocity of 24.0 km/h, the cars pass each other at x = 44.4 m. On the other hand, if the red car has a constant velocity of 48.0 km/h, they pass each other at x = 76.6 m. What are (a) the initial velocity (in km/h) and (b) the (constant) acceleration (in m/s2) of the green car? Include the signs.

Explanation / Answer

I find that if xr= 47.5m, then xg= 192.5m and in the second case xr=76.6m and xg=163.4m so i find time in the 2 cases. 47.5e-3 km / 21km/hr and 76.6e-3km / 44km/hr = .00226hr and .001741 hr respectively , so instantaneous velocity for green in case 1 is 192.5e-3km / .00226 hr = 85.177km/hr and 163.4e-3km / .001741 = 93.854km/hr I use v= v0 + at to find that a= -16718km/hr^2 = -1.29m/s^2 I use the same equation again v= v0 + at to find v0 at the very beginning of the road. 93.854= v0 + (-16718.7km/hr^2)(.001741hr) v0= 122.96km/hr

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