Two antennas located at points A and B are broadcasting radio waves of frequency

Question

Two antennas located at points A and B are broadcasting radio waves of frequency 95.0 MHz, perfectly in phase with each other. The two antennas are separated by a distance d= 9.30 m. An observer, P, is located on the x axis, a distance x= 58.0 m from antenna A, so that APB forms a right triangle with PB as hypotenuse.

a.) What is the phase difference between the waves arriving at P from antennas A and B? Answer: 1.474 radians

b.) Now observer P walks along the x axis toward antenna A. What is P's distance from A when he first observes fully destructive interference between the two waves?

c.) If observer P continues walking until he reaches antenna A, at how many places along the x axis (including the place you found in the previous problem) will he detect minima in the radio signal, due to destructive interference?

Explanation / Answer

L = (2n + 1)*/2. ........(1)
Find the wavelength.
The first destructive interference will occur when L = /2.
Now L = sqrt(9.3^2 +x^2) - x...(2)
Put L = /2 and solve for x.
Repeat the procedure for L = 3/2, 5 /2......until x becomes negative.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.