In the figure, a conducting ring .29m in radius carries a charge of 240nC. A poi

Question

In the figure, a conducting ring .29m in radius carries a charge of 240nC. A point charge Q is placed at the center of the ring. The electric field is equal to zero at field P, which is on the axis of the ring, and .26 m from its center. What is the magnitude of the point charge Q?

Explanation / Answer

field at point P due to ring is Kqcos(angle)/distance^2 = K240nC/0.1517*(0.26/0.389). = K240nC *0.10139, >>> the 0.26/0.389 is the angle theta and the 0.1517 is the distance from p to charge the hypotenuse length formed by the triangle with the radius and p written in unit of meters. due to center charge its Kq/0.26^2 = Kq/0.0676 >>> 0.676 is the square of distance from center to point p. equating these 2 we get the value of q as -1.6449nC

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