Albinism is due to a recessive allele of an autosomal gene. Let \"a\" represent

Question

Albinism is due to a recessive allele of an autosomal gene. Let "a" represent the albino allele and "A" represent the normal (non-albino) allele. If 1 out of every 10,000 people were albino and assuming that the population is in Hardy-Weinberg equilibrium,

A. what would be the phenotype frequencies of albino and non-albino?

B. what would be the allele frequencies of a and of A?

C. what fraction of people can be expected to be of the genotype Aa?

D. what fraction of people can be expected to be of the genotype AA?

Explanation / Answer

A. Since 1 in 10000 people is albino.

Therefore the the phenotypic frequency of albino to non-albino is 1: 9999.

B. Allelic frequency

let a =q2 = 1/10000 therefore q= 0.01

let A = p = 1-q = 0.99

therefore allelic frequency of a= 0.01 and A is 0.99

frequency of heterozygote is 2pq = 0.0198.

C. Fraction of people expected to be of the genotype Aa is = 0.0198 * 10000

= 198 out of 10000

D. Fraction of people expected to be of the genotype Aa is = (p2*10000) = 0 .99* 0.99 * 10000 = 9801 out of 10000.

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