Compute the acceleration of each mass in the figure below, and the tension in th

Question

Compute the acceleration of each mass in the figure below, and the tension in the rope. Let

Explanation / Answer

since m2>m1 the block with mass m1 moves upwards while the block with mass m2 moves downwards considering the free body diagram of block with mass m1=0.71 kg T-m1a1 = m1g =>T+0.71a1=0.71*9.8 =>T+0.71a1=6.958 similarly for m2 T=m2a2+m2g =>T = 2.17a2+2.17*9.81 =>T = 2.17a2+21.266 since force exerted by pulley is same m1a1 = m2a2 => a1 =3.1a2 6.958-0.71(3.1a2) = 2.17a2+21.266 =>a2 = 3.27 m/s^2 a1 = 10.14 m/s^2

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