The velocity selector in the figure is designed to allow charged particles with

Question

The velocity selector in the figure is designed to allow charged particles with a speed of 4500 to pass through undeflected. The magnetic field has a magnitude of 0.97 .

( http://session.masteringphysics.com/problemAsset/1126273/2/Walker4e.ch22.Pr022.jpg )

Part A
Find the magnitude of the required electric field.
Express your answer using two significant figures. Answer in NC


Part B
Find the direction of the required electric field.
Find the direction of the required electric field.
positive direction
negative direction
positive direction
negative direction
positive direction
negative direction

Explanation / Answer

A. Lorentz force law: F = EQ+QvXB (X is vector cross-product operator). Assuming perpendicularity of v, B and E, for zero deflection, E = vB = 4554 V/m. B. If v is directed along +z and B along +x, Fmagnetic is directed along +y when Q is positive. Then Felectric and E must be directed along -y.

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