Consider a closed triangular box resting within a horizontal electric field of m

Question

Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.88 104 N/C as shown in the figure below.

looking for step by step, thank you.

Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.88 104 N/C as shown in the figure below. (a) Calculate the electric flux through the vertical rectangular surface of the box. kN m2/C (b) Calculate the electric flux through the slanted surface of the box. kN.m2/C (c) Calculate the electric flux through the entire surface of the box. kN.m2/C looking for step by step, thank you.

Explanation / Answer

flux = E dot A works E = 6.4 x 10^4 A =(0.03) theta =180 degrees FLUX IN = FLUX OUT NET FLUX =0

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