1) A firehouse shoots water at a speed of 50 m/s from a ground level at an angle

Question

1) A firehouse shoots water at a speed of
50 m/s from a ground level at an angle of 60 above the horizontal. The water is meant to hit a building 10 meters tall that is 20 meters away from the hose. 1: How high is the water stream above the ground when it travelled the 20 meters? 2: If the velocity of the water droplet at that position? 3: if the water misses the building, how far from the hose does it hit the ground. If the water hits the building, how far above the ground does it hit the building?

Explanation / Answer

ucos 60 X t = 20 m t= 0.8 seconds. y = usin 60 t - 1/2 gt^2 = 31.5 m. v= ucos60 i + ( usin 60 t - 9.8t ) = 25 i + ( 35.46 )j m/s = 43.38 m/s D= u^2 sin 120 /g - 20 = 200.9 m to hit the wall, 31.5 mts above.

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