A straight 2.30 wire carries a typical household current of 1.50 (in one directi
ID: 2173447 • Letter: A
Question
A straight 2.30 wire carries a typical household current of 1.50 (in one direction) at a location where the earth's magnetic field is 0.550 gause from south to north.a) Find the magnitude of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from west to east.
b)Find the magnitude of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running vertically upward.
c)Find the magnitude of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from north to south.
please answer all the parts
Explanation / Answer
Given that, Length of the wire l = 2.10 m Current in the wire i = 1.50 A Earth magnetic field B = 0.550 gauss B = 0.550*10-4 T 1) When the current is running from west to east, the angle between the current component and magnetic field component is = 900 Magnitude of the force that our planet's magnetic field exerts on the cord is F = B i l sin F = ( 0.550*10-4 T )(1.50 A)(2.10 m)sin 900 F = 1.7325 *10-4 N 2)When the current is running vertically upward, the angle between the current component and magnetic field component is = 00 Magnitude of the force that our planet's magnetic field exerts on the cord is F = B i l sin F = ( 0.550*10-4 T )(1.50 A)(2.10 m)sin 00 F = 0 N 3) When the current is running from north to south, the angle between the current component and magnetic field component is = 1800 Magnitude of the force that our planet's magnetic field exerts on the cord is F = B i l sin F = ( 0.550*10-4 T )(1.50 A)(2.10 m)sin 1800 F = 0 N
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