)1ftwo peas AAbband na BB aru selfed, resulting in only 1%ofthe F2 progenhingahk
ID: 217563 • Letter: #
Question
)1ftwo peas AAbband na BB aru selfed, resulting in only 1%ofthe F2 progenhingahk. how would you conclude regarding the T ly assorted (B) These two genes are linked, with a genetic C) These two genes are linked, with a genetic distance of 2 cM (D) These two genes are linked, with a genctie distance of 10 cM (E) These two genes are linked, with a genetio distance of 20 cM 12) Why was Mendel successfal in getting the pea experimental results and proponing the two h were confinmed later on? (A) Mendel made sure those seven traits were not sex linked (B) Mendel was smart because he followed the progeny of several genermions wwd cave out with a model that could his explained his results. turmed out to be controlled by independently assorted genes. (D) B and C are correct. (E) All of the above 2. (6 points) Two diploid strawberry plants were thought to be homozygous for two genes controlling fruit flavor (high vs. low quality) and color (orange vs. yellow): one, high quality and orange; and the other, low quality and yellow. In order to determine the patterns of their inheritance, these two plants were cross fertilized and the F1 was self-crossed, resulting in the following F2 progeny: 225 high quality, orange; 80 high quality, yellow, 35 low quality, orange and 80 low quality, yellow. How would you analyze this result, draw a conclusion regarding thwe hese two original parents? The following table of critical values of the X2 distribution may be elpful P-value 0.9 0.016 0.455 2.706 3.8416,63 0.2 .386 4.605 5,.991 7.378 .584 2.366 6.251 7.815 11.345 1.0643.357 7.779 9.488 13.27 1.610 4.35 9.236 11.070 15.086 dr 0.1 0.01Explanation / Answer
11. The answer is C. These two genes are linked, with a genetic distance of 2 cM.
If the genes are assorted indepently, the double recessieve proprotion will be 1/16 = app. 6%, so the first option is wrong.
The Distance between genes = Total number of recombinants/Total number of progeny X 100.
The distance between genes = % of recombination. If Distance is 1 cM, the % of recombination = 1%, as recombinant category contains two genotyeps, the proportion of each genotype = 1/2 = 0.5%, so, this option B also wrong.
The Distance between genes = Total number of recombinants/Total number of progeny X 100.
The distance between genes = % of recombination. If Distance is 2 cM, the % of recombination = 2%, as recombinant category contains two genotyeps, the proportion of each genotype = 2/2 = 1%, so, this option C is correct.
12. The answer is D. B and C.
According to chegg guidelines we have to answer one question at a time.So, post the rest as seperate questions then I can help you.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.