The acceleration due to gravity near a planet\'s surface is known to be 2.90 . I

Question

The acceleration due to gravity near a planet's surface is known to be 2.90 . If the escape speed from the planet is 8.35 , determine its radius. Find the mass of the planet. If a probe is launched from its surface with a speed twice the escape speed and then coasts outward, neglecting other nearby astronomical bodies, what will be its speed when it is very far from the planet? (Neglect any atmospheric effects also.) Under these launch conditions, at what distance will its speed be equal to the escape speed?

Explanation / Answer

a) v = 2gR

8.352 /2 x 2.9 = R

R = 12.02 Km

b) g = GM/R2

M = gR2/G

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