Two straight parallel wires carry currents in opposite directions as shown in th

Question

Two straight parallel wires carry currents in opposite directions as shown in the figure. One of the wires carries a current of I2= 11.9 A. Point A is the midpoint between the wires. The total distance between the wires is d = 12.4 cm. Point C is 4.78 cm to the right of the wire carrying current I2. Current I1is adjusted so that the magnetic field at C is zero.

Calculate the value of the current I1.

=4.28?101A

Calculate the magnitude of the magnetic field at point A.

What is the force between two 1.79 m long segments of the wires?

I've tried the last two over and over and can't figure it out!!!

Explanation / Answer

distance of A from both wire = d/2 = 12.4/2 = 6.2cm at point A B1 = u*I1/2*pi*r (outside the plain) B2= u*I2 / 2*pi*r ( outside the plain) so total B = u*(I1+i2)/ 2*pi*r = = 4*pi*10^-7 *(42.8+11.9) / 2*pi*0.062 = 17.64*10^-5 T answer force between them F/L = Mu*I1*I2/ 2*pi*r F = 1.79 * 4*pi*10^-7 * 42.8*11.9 / 2*pi*0.124 = 1.4704 *10^-3 N

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