Three charges, q1 = 7.07nC, q2 = -4.64nC and q3 = 2.66nC are at the corners of a

Question

Three charges, q1 = 7.07nC, q2 = -4.64nC and q3 = 2.66nC are at the corners of an equilateral triangle, as shown in the figure above.

The angle is 60.0o and L = 0.412 m. We are interested in the point midway between the charges q1 and q2 on the x axis.

a)For starters, calculate the magnitude of the electric field due only to charge q3 at this point.

b) Now calculate the magnitude of the electric field from all three charges at a point midway between the two charges on the x axis.

c) Calculate the angle of the electric field relative to the positive (to the right) x-axis, with positive values up (Counter-Clock Wise) and negative down (Clockwise). (enter the answer with units of deg)

d) If a tiny particle with a charge q = 1.43nC were placed at this point midway between q1 and q2, what is the magnitude of the force it would feel?

Explanation / Answer

F = Q/(4*Eo *r^2)    r^2 = 5*L^2/4

(a) F/q = 116.68 along y axis(negative)

(b) F/q = 2481 along x axis

resultant electric field F/q = 2483.98

(c) - 2.67o

(d) F = 3.55 *10-5 N

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