the boy weighs 150 lb and the girl 100 lb. First the boy jumps from the boat wit

Question

the boy weighs 150 lb and the girl 100 lb. First the boy jumps from the boat with a relative horizontal speed of 10 ft/s and then the girl jumps with relative speed of 8 ft/s. if the boat weighs 400 lb, neglecting water resistance, what is the final speed of the boat. Assume the boat is at rest before the boy jumps.

Explanation / Answer

conserving momentum from an inertial frame initial momentum = 0 kg m /s final momentum = 150*10 + 500*v => v = - 3 ft/s now conserving momentum from the non inertial frame of the boat if we are looking at the situation while sitting on the boat the girl, according to the question appears to be jumping at 8 ft/s so initial momentum = 0 final momentum = 100*8 + 400*v => v = -2 ft/s the total speed of the boat = speed of the frame + the speed after the girl jumps => speed of the boat = 5 ft/s in the opposite direction to which the boy and the girl jump

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