As the driver steps on the gas pedal, a car of mass 1 180 kg accelerates from re

Question

As the driver steps on the gas pedal, a car of mass 1 180 kg accelerates from rest. During the first few seconds of motion, the car's acceleration increases with time according to the expression below, where t is in seconds and a is in m/s2. a = 1.14 t - 0.210 t2 + 0.240 t3 What is the change in kinetic energy of the car during the interval from t = 0 to t = 1.50 s? Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. J What is the minimum average power output of the engine over this time interval? differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. W

Explanation / Answer

v=(1.14t-0.21t2+0.24t3)dt

integrating from 0 to 1.5

v=1.35

initial v=0

so changee in K.E=1180*1.352/2=1075.275 J

2)P=K.E/t=1075.275/1.5 =716.85 W

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