As shown, a rope is attached to a l = 17.0ft high shed that is to be relocated.

Question

As shown, a rope is attached to a l = 17.0ft high shed that is to be relocated. A man pulls on the end of the rope at point A. the rope is attached to the shed at point B. (Figure 1) As the man pulls on the rope, it creates an angle theta with the horizontal. The end of the rope is located at x = 8.00ft from the shed and y = 4.00ft off the ground. The man pulls on the rope with a force of magnitude F = 55.01b Using the principle of transmissibility, the force F can be slid along its line of action to point B. At point B. the force F creates an angle phi with the shed. (Figure 3) What is MFx, the contribution to the moment about point O made by the x component of the force F at point B? What is MFy, the contribution to the moment about point O made by the y component of the force F at point B? What is the total moment M due to the force F about point O? Assume that moments acting counterclockwise about point O are positive whereas moments acting clockwise are negative. Express your answers numerically in pound-feet to three significant figures separated by commas.

Explanation / Answer

Fx=F sin(phi) tan(phi)=8/13 Fx=28.82lb Mxo=Fx*17=489.94 lb-ft Myo=0 Mo=Mxo=489.94 lb-ft

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