A tennis player tosses a tennis ball straight up and then catches it after 1.65

Question

A tennis player tosses a tennis ball straight up and then catches it after 1.65 s at the same height as the point of release.

(a) What is the acceleration of the ball while it is in flight?
magnitude (m/s^2)= ?
direction =is it upward, downward or the magnitude is zero?

(b) What is the velocity of the ball when it reaches its maximum height?
magnitude (m/s^2)= ?
direction = is it upward, downward or is the magnitude zero

(c) Find the initial velocity of the ball
m/s upward = ?.

(d) Find the maximum height it reaches
m= ?.

Explanation / Answer

a) accelration due to gravity 9.8 m/s^2 always towards downwards b)zero c)2* u /9.8 = 1.65 u = 8.085 m/s d)max height = 8.085 *8.085 / (2*9.8) = 3.335 m

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