M B = ME A = ME D = W con B-C = v C = A small ball with a mass of 3.6 kg moves a

Question

MB=

MEA=

MED=

WconB-C=

vC=

A small ball with a mass of 3.6 kg moves along with the energy curve shown to the left, while not being subjected to any non-conservative forces. At point B it has a velocity of 2.9 m/sec. 1) What is the mechanical energy of the object at point B? MB= 2) What is the mechanical energy of the object at point A? MEA= 3) What is the mechanical energy of the object at point D? MED= 4) What is the net work done by conservative forces on the object between points B and C? WconB-C= J 5) What is the velocity of the object at point C? vC= m/sec

Explanation / Answer

1. m.e = k.e +p.e

= 2 + 1/2*3.6*2.9^2

= 17.138 J

2. same as 17.138 J

3. 17.138 J

4. net work done = k.e

= k.e at B - k.e at C

= 15.138 - 11.138

= 4 J

5. velocity at C, ke at C = 11.138

= 1/2*3.6*v^2

v = 2.487 m/s

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