The following information may be useful in solving this problem e = 1.6 X 10^-29

Question

The following information may be useful in solving this problem e = 1.6 X 10^-29 C. The mass of a chloride ion is approximately 5.9 X 10^-26 kg.
A thin circular sheet of glass of diameter 3 meters is rubbed with a cloth on one surface and becomes charged uniformly. A chloride ion (a chlorine atom that has gained on electron) passes near the glass sheet. When the chloride ion is near the center of the sheet, at a location 0.8 mm from the sheet, it experiences an acceleration of 8.47 x 10^10 m/s^2 toward the sheet.
A) Determine the magnitude and direction of the electric field at the location of the chloride ion.
B) Determine the total excess charge on the surface of the glass disk (including sign).
C) What is the potential difference between the location of the chloride ion and the surface of the disk?

Explanation / Answer

Let V be the velocity when it reaches the surface v = ?2as = 11.64 X 10^ 3.conserving energy ; Change in potential energy = Change in potential energy ===> P = 1/2m(V^2 - u^2) = 1/2mV^2 = 4 X 10^22 J potential difference = Potential energy/q = 4 X 10^22/-1.6 X 10^-29 = - 2.49 X 10^51 J/C

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