A 2.0 kg block sits on a 4.0 kg block that is on a frictionless table. The coeff

Question

A 2.0 kg block sits on a 4.0 kg block that is on a frictionless table. The coefficients of friction between the blocks are mu s = 0.90 and mu K = 0.10. What is the maximum force F that can be applied to the 4.0 kg block if the 2.0 kg block is not to slide? N If F is half this value, find the acceleration of each block. m/s2 (2.0 kg block) m/s2 (4.0 kg block) Find the magnitude of the force of friction acting on each block. N (2.0 kg block) N (4.0 kg block) If Fis twice the value found in (a), find the acceleration of each block. m/s2 (2 kg block) m/s2 (4 kg block)

Explanation / Answer

F/(M+m)*m=us*m*g so F=52.92

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.