Just after a motorcycle rides off the end of a ramp and launches into the air, i

Question

Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 7400 rev/min. The motorcycle rider forgets to throttle back, so the engine's angular speed increases to 12900 rev/min. As a result, the rest of the motorcycle (including the rider) begins to rotate clockwise about the engine at 3.70 rev/min. Calculate the ratio IE/IM of the moment of inertia of the engine to the moment of inertia of the rest of the motorcycle (and the rider). Ignore torques due to gravity and air resistance.

Explanation / Answer

angular momentum is conserved as no external force is there in air. hence IE *12900 =IM *3.7 hence IE/IM =3.7/12900 =2.87*10^-4

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