A box starts out at the top of a frictionless ramp, then slides down. The ramp h

Question

A box starts out at the top of a frictionless ramp, then slides down. The ramp has a heighth=3meters and a slope of5degrees with respect to the ground. The box has a mass of3kg. The system is under normal gravity, sog= 9.81 m/s2Let the potential energy be zero at the bottom.

a) What is the initial gravitational energy of the box at the top of the ramp?
J

b) What is the kinetic energy of the box at the bottom of the ramp?
J

c) What is the total mechanical energy of the box at the bottom of the ramp?
J

d) What is the total mechanical energy of the box at the top of the ramp?
J

e) What does this make the velocity of the box at the bottom?
m/s

f) What is this velocity if the box starts with a mass of9kg?
m/s

Explanation / Answer

a)U=mgh=3*9.8*3=88.2J

b)KE=U=88.2J

c)Mechanical energy at bottom=88.2J

d)Mechanical energy at bottom=88.2J

e)v=sqrt(2gh)=7.67m/s

f)v=sqrt(2gh)=7.67m/s

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