In the ground state, the outermost shell (n = 1) of helium (He) is filled with e

Question

In the ground state, the outermost shell (n = 1) of helium (He) is filled with electrons, as is the outermost shell ( n = 2) of neon (Ne). The full outermost shells of these two elements distinguish them as the first two so-called "nobel gases." Suppose that the spin quantum ms had three possible values, rather than two. If that were the case, which elements would be (a) the first and (b) the second noble gases? Assume that the possible values for the other three quantum numbers are unchanged, and that the Pauli exclusion principle still applies. First noble gas Second noble gas Hydrogen Helium Lithium Beryllium Boron Carbon Nitrogen Oxygen Fluorine Neon Sodium Magnesium Aluminum Silicon Phosphorus Sulfur Chlorine Argon

Explanation / Answer

Beryllium and phosphorous

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