A circuit contains two resistors (10 ? and 20 ?) and two capacitors (12?F and 6?

Question

A circuit contains two resistors (10 ? and 20 ?) and two capacitors (12?F and 6?F) connected to a 6 V battery, as shown in the diagram above. The circuit has been connected for a long time. A) Calculate the total capacitance of the circuit. B) Calculate the current in the 10 Ohlm resistor C)Calculate the potential difference between point A and B D)Calculate the charge stored on a one plate of the 6uF capacitor E)The wire is cut at point P. Will the potential difference between points A and B increase, decrease, or remain the same?

Explanation / Answer

A) Since capacitors are in series, 1/TC = 1/12 + 1/6
TC( Total capacitance) = 4F

B) After long time, no current flows through AB.

Thus, Total resistance = 30

Current through 10 = 6/30 = 0.2 A

C) PD between A and B = 0.2*20 = 4 V

D) Charge stored = 4/3*6*10-6 = 8*10-6 C

E) Remain the same

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