A cannon is used to launch a cannonball from the top of a hill. Initially, the c

Question

A cannon is used to launch a cannonball from the top of a hill. Initially, the cannon is aimed parallel to the ground (0 degrees). After the cannon is fired, the angle (alpha) of the cannon is increased by 15 degrees until the cannon reaches an angle of 75 degrees. The cannon always launches the cannonball at the same speed. The horizontal displacement (d) of the cannon ball as below answer questions a-d SHOW ALL YOUR WORK Angle (Degrees) Displacement (m) Time (sec) 0 14 1.4 15 16.4 1.7 30 17.3 2 45 16.2 2.3 60 12.6 2.5 75 6.9 2.7 a. Approximately how high above the ground is the cannon when it fires the cannon ball? (A)5m (B)7m (C)10m (D)15m b. what is the initial speed of the cannonball when it leaves the cannon? (A) 5m/s (B)10m/s (C)15ms (D) 20m/s c. the cannonball would reach it maximum height when fired from which of the following angles? (A) 25 degrees (B)30 degrees (c) 45 degrees (D) 90 degrees d. which of the following graphs most accuretely represents the relationship between the horizontal displacement of the projectile and the angle (alpha)?

Explanation / Answer

For Range use V^2 sin 2angle / g ........where angle is elevation angle. Velocity : Horizontal component = Vcos(angle) Vertical Component = Vsin(angle) For Maximum Height = V^2sin^2(angle) / 2g

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