A 0.327-kg volleyball approaches a player horizontally with a speed of 13.2 m/s.

Question

A 0.327-kg volleyball approaches a player horizontally with a speed of 13.2 m/s. The player strikes the ball with her fist and causes the ball to move in the opposite direction with a speed of 22.0 m/s. (a) What impulse is delivered to the ball by the player? (b) If the player's fist is in contact with the ball for 0.0600 s, find the magnitude of the average force exerted on the player's fist. N

Explanation / Answer

a) By Impulse(I) = ?P = m x ?v = m x [v(final) - v(initial)] =>I = 0.329 x [-22-12.9] =>I = -11.4821 N-s [-ve indicating the direction is opposite to the initial direction of ball]----------- b) By F = ?P/?t = -11.4 /0.06 = -191.36 Newton [-ve indicating the direction is opposite to the initial direction of ball]

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