NOTE: The data for this problem is written in exponential form. For example: 2.1

Question

NOTE: The data for this problem is written in exponential form. For example: 2.1e-15 means 2.1x10^-15. A certain nucleus at rest suddenly decays into three particles, two of which are charged and can be easily detected. The data gathered for these two particles is: - Particle 1 has mass m1 = 2.85e-25 kg moving at speed v1 = 4.33e+06 m/s at ?1 = 41.4o. - Particle 2 has mass m2 = 1.3e-25 kg moving at speed v2 = 7.87e+06 m/s at ?2 = 236o. Find p3, the momentum of the third piece. ________ i kg-m/s + ______j kg-m/s

Explanation / Answer

for d, momentum is conserved in all directions, so... Break things down into the x (i) and y (j) components X (i): 2.69e-25*5.03e6*cos(58.2)+1.47e-25*8.23e^6*cos(235)= negative momentum in i direction do the same for the Y (j) direction ---------- e) use conservation of momentum (but use speeds relative to the point in the water (if he's walking at 1 m/s relative to the boat, he may only be traveling 0.7 m/s relative to the water, so his momentum would be 0.7*mass. (I just made these numbers up, but you get the point) ------ coefficient of restitution = (final velocity of object 2 - final velocity of object 1)/(initial velocity of a - initial velocity of b)

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