A conducting rod slides down between two frictionless vertical copper tracks at

Question

A conducting rod slides down between two frictionless vertical copper tracks at a constant speed of 4.3 m/s perpendicular to a 0.55-T magnetic field. The resistance of the rod and tracks is negligible. The rod maintains electrical contact with the tracks at all times and has a length of 1.2 m. A 0.81-? resistor is attached between the tops of the tracks. (a) What is the mass of the rod? (b) Find the change in the gravitational potential energy that occurs in a time of 0.20 s. (c) Find the electrical energy dissipated in the resistor in 0.20 s.

Explanation / Answer

The work done to lift the box to that height is stored in the body as the potential energy. Hence the work done is 400 J. As for the height, potential energy is given by m*g*h, and the weight is given by m*g (=200N here). Therefore, 200h = 400 => h = 2m.

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