In Figure 11-48, two skaters, each of mass 60 kg, approach each other along para

Question

In Figure 11-48, two skaters, each of mass 60 kg, approach each other along parallel paths separated by 2.0 m. They have opposite velocities of 1.6 m/s each. One skater carries one end of a long pole with negligible mass, and the second skater grabs the other end of it as she passes. The skaters then rotate around the center of the pole. Assume that the friction between skates and ice is negligible. Fig. 11-48 (a) What is the angular momentum of the two skaters around their center of mass before the second skater grabs the pole? Js (b) What is the angular momentum of the two skaters around their center of mass after the second skater grabs the pole? Js (c) What is the angular velocity of the two skaters around their center of mass after the second skater grabs the pole? J

Explanation / Answer

(a) Angular momentum of each skater = mvr = 60*1.6*1 = 96 Js ...(b) Angular momentum of each skater will remain the same i.e 96 Js ..(c) Angular velocity = v/r = 1.6/1 = 1.6 rad/s

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