A block of mass M is being pushed along a rough, horizontal surface by an applie
ID: 2190183 • Letter: A
Question
Explanation / Answer
Since the block is moving with constant speed , so the net force acting on the block is zero. So (p) is correct .
The net force acting on the block in y direction is Fsin + Mg . So normal reaction is Fsin + Mg and
friction = k(Fsin + Mg ) . so option (q) is incorrect.
The component of the applied force in x direction is Fcos . As block moves with constant speed. So net force in x direction should be zero. So fricton which opposes the force applied in x-direction should be Fcos. So option (r) is correct
The normal force acting is Mg + Fsin. So option (s) is incorect.
So (p) & (r ) are correct . Option (C)
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.