A 25 kg box is sliding down an ice covered hill. When it reaches point A, the bo

Question

A 25 kg box is sliding down an ice covered hill. When it reaches point A, the box is moving at 11 m/s. Point A is at the bottom of a circular arc that has a radius R=7.5m. What is the magnitude of the Fn on the box at Point A? a. 250 N b. 280 N c. 400 N d. 650N e. 900 N

A 25 kg box is sliding down an ice covered hill. When it reaches point A, the box is moving at 11 m/s. Point A is at the bottom of a circular arc that has a radius R=7.5m. What is the magnitude of the Fn on the box at Point A? a. 250 N b. 280 N c. 400 N d. 650N e. 900 N

Explanation / Answer

We have the regular weight of the box and the centripetal force of the box both pushing down at point A. Point A is pushing up with the normal force. F = ma = m v^2/r + mg mg = 25kg*9.8m/s^2 = 245N mv^2/r = 25kg*(121m^2/s^2)/7.5m = 403N F = 650N, choice d

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