A .530 kg block slides on a frictionless horizontal surface with a speed of 1.40

Question

A .530 kg block slides on a frictionless horizontal surface with a speed of 1.40 m/s. The block encounters an unstretched spring and compresses it 20.0 cm before coming to rest. Part A) What is the force constant of this spring? k=________N/m

Part B) For what length of time is the block in contact with the spring before it comes to rest?

t=________sec

Part C) If the force constant of the spring is increased, does the time required to stop the block increase, decrease, or stay the same.

Choices:

A) Increases

B) Decreases

C) Stays the same

Explanation / Answer

A 0.530 kg block slides on a frictionless horizontal surface with a speed of 1.40 m/s. The block encounters an unstretched spring and compresses it 20.0 cm before coming to rest. Part A) What is the force constant of this spring? k=________N/m

m v^2 = k x^2

>>>> k = m v^2 /x^2 = 0.530*1.40*1.40/(0.2*0.2) = 25.97 26.0 N/m

Part B) For what length of time is the block in contact with the spring before it comes to rest?

t=________sec

T = 2/ =2(m/k) = 2*3.14*(0.530/25.97) = 0.89757 s

>> t = T/2 = 0.89757/2 = 0.449 s

Part C) If the force constant of the spring is increased, does the time required to stop the block increase, decrease, or stay the same.

Choices:

A) Increases

B) Decreases

C) Stays the same

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