A textbook of mass 2.05 kg rests on a frictionless, horizontal surface. A cord a

Question

A textbook of mass 2.05 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.190m, to a hanging book with mass 2.94 kg. The system is released from rest, and the books are observed to move a distance 1.29m over a time interval of 0.760s. 1) What is the tension in the part of the cord attached to the textbook? in N 2) What is the tension in the part of the cord attached to the book? in N 3) What is the moment of inertia of the pulley about its rotation axis? (freefall acceleration to be g = 9.8 m/s^2) kg*m^2

Explanation / Answer

Following method will be followed to solve this question./.............. First the acceleration of the system comes from s = 1/2*a*(?t)^2 so a = 2*s/(?t)^2 Now summing forces about M_1 we have T1 = M_1*a = M_1*2*s/(?t)^2 2. Now summing about m_2 we get m_2*g - T2 = m_2*a so T2 = m_2*(g - 2*s/(?)^2) 3. Now summing torques about the pulley we get (T2 - T1)*d/2 = I*a but a = a/d/2 so (T2 - T1)*d/2 = I*2*s/(?t)^2/(d/2) So I = (T2 - T1)*(d/2)^2*(?t)^2/2 = (T2 - T1)*d^2/8*(?t)^2

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