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Blocks A(mass 5.00 ) and (mass 15.00 ) move on a frictionless, horizontal surfac

ID: 2191879 • Letter: B

Question

Blocks A(mass 5.00 ) and (mass 15.00 ) move on a frictionless, horizontal surface. Initially, block B at rest and block A is moving toward it at 8.00m/s blocks are equipped with ideal spring bumpers. The collision is head-on, so all motion before and after the collision is along a straight line. Let +x be the direction of the initial motion of A. Find the maximum energy stored in the spring bumpers and the velocity of each block at that time. Find the maximum energy. Ub=? Find the velocity of A . Va=? Find the velocity of B. Vb=? Find the velocity of each block after they have moved apart. Find the velocity of A. Va=? Find the velocity of B. Vb=?

Explanation / Answer

from conservation of energy we have: for maximum compresion block when collides goes down to rest(block A) so we have: .5 * 5*^2 = .5*K*x^2....where K is spring constant( that should be given in question) and x is compression. for this condition velocity of A and B is zero. after seperation: .5 * 5*^2 = .5*5^v^2 + .5*15*v'^2, also from momentum conservation we have: .5*8 = 5*v + 15*v', from here find v( velocity of A) and v' (velocity of B)

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