A 1.90-kg ball, moving to the right at a velocity of +3.45 m/s on a frictionless

Question

A 1.90-kg ball, moving to the right at a velocity of +3.45 m/s on a frictionless table, collides head-on with a stationary 9.00-kg ball. Find the final velocities of (a) the 1.90-kg ball and of (b) the 9.00-kg ball if the collision is elastic. (c) Find the magnitude and direction of the final velocity of the two balls if the collision is completely inelastic. I found b & c, but I do not know how to find a.

Explanation / Answer

as the collision is elastic apply the law of conservation of linear momentum m1u1 + m2u2 = m1v1 + m2v2 1.9 * 3.45 = 1.9 * v1 + 9 * v2 ------> equation 1 also apply the law of conservation of energy (1/2)m1u1^2 + (1/2)m2u2^2 = (1/2)m1v1^2 + (1/2)m2v2^2 1.9 * 3.45^2 = 1.9 * v1^2+ 9 * v2^2 -----> equation 2 solving the above two equation we get a) v1 = - 2.24 m/s b) v2 = +1.2 m/s

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