A small metal cylinder rests on a circular turntable that is rotating at a const

Question

A small metal cylinder rests on a circular turntable that is rotating at a constant speed as illustrated in the diagram The small metal cylinder has a mass of 0.20 kg, the coefficient of static friction between the cylinder and the turntable is 0.080, and the cylinder is located 0.15 m from the center of the turntable. Take the magnitude of the acceleration due to gravity to be 9.81m/s^2 What is the maximum speed Vmax, that the cylinder can move along its circular path without slipping off the turntable? .

Explanation / Answer

Here

Frictional Force is Provides the Necessary Centripetal Force

Therefore

µmg = mv^2/r

Therefore

µg = v^2/r

Therefore

v = sqrt(0.080*9.81*0.15)

= 0.34310 m/sec

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