A single square copper has a mass of 17.0-g and each side measures 6.2 cm. The c

Question

A single square copper has a mass of 17.0-g and each side measures 6.2 cm. The coil has a resistance of 0.04 ?. The coil starts right between the poles of a bar magnet, and it is pulled upward with a constant speed of 8.4 m/s. When the coil is right between the magnetic poles, the average magnetic field is 0.45 T. When the coil is 0.20 m above the center of the poles, the magnetic field is equal to 0.12 T. (i) What is the time the coil takes to rise the 0.20 m? (ii) What is the average induced current in the coil? (iii) While the coil is pulled upward, do you expect the tension to be LARGER, SMALLER, or THE SAME as the weight of the coil? (iv) If the difference between the magnetic field acting at the top and bottom of the coil is 0.07 T, calculate the tension force

Explanation / Answer

(i) t = S / V = .2 / 8.4 = .0238 sec (ii) E = (B1 - B2) * A / t E = (.45 - .12) * .062^2 / .0238 = .0533 V I = E / R = .0533 / .04 = 1.33 amps (iii) I would expect the tension to be larger because of the additional energy being lost in the resistor (iv) F = I L B force on wire in magnetic field F = I L (B2 - B1) = 1.33 * .062 * .07 = .00577 N Add this to the weight of the loop if the total tension is required

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