A 1.4 kg mass is moving towards the right at a speed 2 m/s on a flat, horizontal

Question

A 1.4 kg mass is moving towards the right at a speed 2 m/s on a flat, horizontal, frictionless table. It collides perfectly ellastically with a 0.4 kg mass which is initially at rest. The surface of the table is 1.5 m above the floor. a)After the collision what is the speed of the 1.4 kg mass? b)After the collision what is the speed of the 0.4 kg mass? c)At what distance from the base of the table (directly below the edge of the table's surface) does the 1.4 kg mass hit the floor? d)At what distance from the base of the table (directly below the edge of the table's surface) does the 0.4 kg mass hit the floor?

Explanation / Answer

say v1=velocity of 1.4 kg mass after collsion
v2=velocity of 0.4 kg mass after collsion
momentum=>
1.4*2=1.4v1+0.4v2=2.8
KE=>
.5*1.4*2^2=.5*1.4*v1^2+.5*.4*v2^2
solving for v1 and v2
a)v1 -> 1.11 m/s

b)v2 -> 3.11 m/s

c)x=v1*t ;t=(2h/g)=.5533 sec

x=0.6142 m

d)x=v2*t=1.721 m

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