We measure a particles velocity in the x direction to be given by vx(t) = bt ?c/

Question

We measure a particles velocity in the x direction to be given by vx(t) = bt ?c/t2 , where b and c are constants. a) Find the particles acceleration in the x direction as a function of time. b) Find the particles position in the x direction as a function of time. c) If the particle is also undergoing motion in the y direction under the influence of gravity (normal y motion), find the magnitude of the velocity of the particle after 1 second, assuming it started from rest in the y direction, and b=c=1.

Explanation / Answer

a)ax(t)=dvx(t)/dt=b+2c/t^3 b)x(t)=bt^2/2+c/t c)

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