Water flows through the horizontal tube pictured below so that the difference in

Question

Water flows through the horizontal tube pictured below so that the difference in pressure between a point in the wider portion and a point in the constricted portion is 4000 Pa. If the diameters of the two sections are 8.50 cm and 5.25 cm, find: (a) the flow rate of the water through the pipe and (b) the speed of the water in each section.

Explanation / Answer

b)A1*v1 = A2*v2 =>d1^2*v1 = d2^2*v2 =>(5.25^2)*v1 = (8.5^2)*v2 =>v2 = 0.381487889*v1 Apply Bernoulli equation to get, P1 + 0.5*rho*v1^2 = P2+0.5*rho*v2^2 =>0.5*1000*(1-(0.381487889^2))*v1^2 = 4000 => v1 = 3.059830354 m/s v2 = 1.167288223 m/s a)the flow rate of the water through the pipe = rho*A*v = 1000*(22/7)*((5.25/200)^2)*3.059830354 = 6.62644511 L/s

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