(a) What is the tangential acceleration of a bug on the rim of a 12.0-in.-diamet

Question

(a) What is the tangential acceleration of a bug on the rim of a 12.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 79.0 rev/min in 4.20 s? m/s2 (b) When the disk is at its final speed, what is the tangential velocity of the bug? m/s (c) One second after the bug starts from rest, what is its tangential acceleration? m/s2 (d) One second after the bug starts from rest, what is its centripetal acceleration? m/s2 (e) One second after the bug starts from rest, what is its total acceleration? m/s2

Explanation / Answer

Ans: a = ?w/?t = 77 . 2 p / 60 . 4 = 2.02 rad/s a = a . r = 2.02 . 0.1524 = 0.31 m/s/s b) v = w . r = 77 . 2p . 0.1524 / 60 = 1.23 m/s c) You are told the acceleration is uniform = 0.31 m/s/s d) v^2 / r = 0.31^2 / 0.1524 = 0.63 m/s/s e) v 0.31^2 + 0.63^2 = 0.703 m/s/s

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