A square loop of wire is rotating around its vertical axis in a magnetic field o

Question

A square loop of wire is rotating around its vertical axis in a magnetic field of strength B = 0.06 T as shown in View A. The angular frequency of rotation is omega = 50 rad/s and the loop has a resistance of R = 5 ohm . The length of one side of the square loop is W = 0.05 m. At the instant of time when the normal to the loop makes an angle of theta = 30degrees with respect to the B field, as shown in View B where 'N' represents the normal, calculate the current flowing in the loop. Note: View A would be the side view if theta = 90degrees or 270degrees.

Explanation / Answer

I got 7.5e-4 :)

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